31=3(1+2m)+5(m-1)

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Solution for 31=3(1+2m)+5(m-1) equation: 



31=3(1+2m)+5(m-1)

We move all terms to the left:

31-(3(1+2m)+5(m-1))=0

We add all the numbers together, and all the variables

-(3(2m+1)+5(m-1))+31=0



We calculate terms in parentheses: -(3(2m+1)+5(m-1)), so:

3(2m+1)+5(m-1)

We multiply parentheses

6m+5m+3-5

We add all the numbers together, and all the variables

11m-2

Back to the equation:

-(11m-2)



We get rid of parentheses

-11m+2+31=0

We add all the numbers together, and all the variables

-11m+33=0

We move all terms containing m to the left, all other terms to the right

-11m=-33

m=-33/-11

m=+3

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