31=2(t-1)+13

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Solution for 31=2(t-1)+13 equation: 



31=2(t-1)+13

We move all terms to the left:

31-(2(t-1)+13)=0



We calculate terms in parentheses: -(2(t-1)+13), so:

2(t-1)+13

We multiply parentheses

2t-2+13

We add all the numbers together, and all the variables

2t+11

Back to the equation:

-(2t+11)



We get rid of parentheses

-2t-11+31=0

We add all the numbers together, and all the variables

-2t+20=0

We move all terms containing t to the left, all other terms to the right

-2t=-20

t=-20/-2

t=+10

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