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315=(2x+4)(x-1)
We move all terms to the left:
315-((2x+4)(x-1))=0
We multiply parentheses ..
-((+2x^2-2x+4x-4))+315=0
We calculate terms in parentheses: -((+2x^2-2x+4x-4)), so:We get rid of parentheses
(+2x^2-2x+4x-4)
We get rid of parentheses
2x^2-2x+4x-4
We add all the numbers together, and all the variables
2x^2+2x-4
Back to the equation:
-(2x^2+2x-4)
-2x^2-2x+4+315=0
We add all the numbers together, and all the variables
-2x^2-2x+319=0
a = -2; b = -2; c = +319;
Δ = b2-4ac
Δ = -22-4·(-2)·319
Δ = 2556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2556}=\sqrt{36*71}=\sqrt{36}*\sqrt{71}=6\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6\sqrt{71}}{2*-2}=\frac{2-6\sqrt{71}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6\sqrt{71}}{2*-2}=\frac{2+6\sqrt{71}}{-4} $
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