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31-4x=5-5(1-5x)
We move all terms to the left:
31-4x-(5-5(1-5x))=0
We add all the numbers together, and all the variables
-4x-(5-5(-5x+1))+31=0
We calculate terms in parentheses: -(5-5(-5x+1)), so:We add all the numbers together, and all the variables
5-5(-5x+1)
determiningTheFunctionDomain -5(-5x+1)+5
We multiply parentheses
25x-5+5
We add all the numbers together, and all the variables
25x
Back to the equation:
-(25x)
-29x+31=0
We move all terms containing x to the left, all other terms to the right
-29x=-31
x=-31/-29
x=1+2/29
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