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31+25x+2x^2=7x-9
We move all terms to the left:
31+25x+2x^2-(7x-9)=0
We get rid of parentheses
2x^2+25x-7x+9+31=0
We add all the numbers together, and all the variables
2x^2+18x+40=0
a = 2; b = 18; c = +40;
Δ = b2-4ac
Δ = 182-4·2·40
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2}{2*2}=\frac{-20}{4} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2}{2*2}=\frac{-16}{4} =-4 $
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