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30x^2-54x+18=-6
We move all terms to the left:
30x^2-54x+18-(-6)=0
We add all the numbers together, and all the variables
30x^2-54x+24=0
a = 30; b = -54; c = +24;
Δ = b2-4ac
Δ = -542-4·30·24
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6}{2*30}=\frac{48}{60} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6}{2*30}=\frac{60}{60} =1 $
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