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30x-6x^2-36=0
a = -6; b = 30; c = -36;
Δ = b2-4ac
Δ = 302-4·(-6)·(-36)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*-6}=\frac{-24}{-12} =+2 $
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