30x-(15(x-2)-6(3x+1)+6(2+x))=240

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Solution for 30x-(15(x-2)-6(3x+1)+6(2+x))=240 equation: 



30x-(15(x-2)-6(3x+1)+6(2+x))=240

We move all terms to the left:

30x-(15(x-2)-6(3x+1)+6(2+x))-(240)=0

We add all the numbers together, and all the variables

30x-(15(x-2)-6(3x+1)+6(x+2))-240=0



We calculate terms in parentheses: -(15(x-2)-6(3x+1)+6(x+2)), so:

15(x-2)-6(3x+1)+6(x+2)

We multiply parentheses

15x-18x+6x-30-6+12

We add all the numbers together, and all the variables

3x-24

Back to the equation:

-(3x-24)



We get rid of parentheses

30x-3x+24-240=0

We add all the numbers together, and all the variables

27x-216=0

We move all terms containing x to the left, all other terms to the right

27x=216

x=216/27

x=8

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