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30t=45(t-1/4)
We move all terms to the left:
30t-(45(t-1/4))=0
We add all the numbers together, and all the variables
30t-(45(+t-1/4))=0
We multiply all the terms by the denominator
30t*4))-(45(+t-1=0
We add all the numbers together, and all the variables
t+30t*4))-(45(-1=0
Wy multiply elements
120t^2+t-1=0
a = 120; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·120·(-1)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{481}}{2*120}=\frac{-1-\sqrt{481}}{240} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{481}}{2*120}=\frac{-1+\sqrt{481}}{240} $
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