30d2+7d-15=0

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Solution for 30d2+7d-15=0 equation:



30d^2+7d-15=0
a = 30; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·30·(-15)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-43}{2*30}=\frac{-50}{60} =-5/6 $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+43}{2*30}=\frac{36}{60} =3/5 $

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