30=16t2+56t+6

Solution for 30=16t2+56t+6 equation:

30=16t^2+56t+6

We move all terms to the left:

30-(16t^2+56t+6)=0

We get rid of parentheses

-16t^2-56t-6+30=0

We add all the numbers together, and all the variables

-16t^2-56t+24=0

a = -16; b = -56; c = +24;
Δ = b2-4ac
Δ = -562-4·(-16)·24
Δ = 4672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4672}=\sqrt{64*73}=\sqrt{64}*\sqrt{73}=8\sqrt{73}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8\sqrt{73}}{2*-16}=\frac{56-8\sqrt{73}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8\sqrt{73}}{2*-16}=\frac{56+8\sqrt{73}}{-32}
$