30=-8y+2(y-3)

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Solution for 30=-8y+2(y-3) equation:



30=-8y+2(y-3)
We move all terms to the left:
30-(-8y+2(y-3))=0
We calculate terms in parentheses: -(-8y+2(y-3)), so:
-8y+2(y-3)
We multiply parentheses
-8y+2y-6
We add all the numbers together, and all the variables
-6y-6
Back to the equation:
-(-6y-6)
We get rid of parentheses
6y+6+30=0
We add all the numbers together, and all the variables
6y+36=0
We move all terms containing y to the left, all other terms to the right
6y=-36
y=-36/6
y=-6

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