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30=(5+0.4x)x
We move all terms to the left:
30-((5+0.4x)x)=0
We add all the numbers together, and all the variables
-((0.4x+5)x)+30=0
We calculate terms in parentheses: -((0.4x+5)x), so:We get rid of parentheses
(0.4x+5)x
We multiply parentheses
0x^2+5x
We add all the numbers together, and all the variables
x^2+5x
Back to the equation:
-(x^2+5x)
-x^2-5x+30=0
We add all the numbers together, and all the variables
-1x^2-5x+30=0
a = -1; b = -5; c = +30;
Δ = b2-4ac
Δ = -52-4·(-1)·30
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{145}}{2*-1}=\frac{5-\sqrt{145}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{145}}{2*-1}=\frac{5+\sqrt{145}}{-2} $
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