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300=3.14r^2
We move all terms to the left:
300-(3.14r^2)=0
We get rid of parentheses
-3.14r^2+300=0
a = -3.14; b = 0; c = +300;
Δ = b2-4ac
Δ = 02-4·(-3.14)·300
Δ = 3768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3768}=\sqrt{4*942}=\sqrt{4}*\sqrt{942}=2\sqrt{942}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{942}}{2*-3.14}=\frac{0-2\sqrt{942}}{-6.28} =-\frac{2\sqrt{942}}{-6.28} =-\frac{\sqrt{942}}{-3.14} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{942}}{2*-3.14}=\frac{0+2\sqrt{942}}{-6.28} =\frac{2\sqrt{942}}{-6.28} =\frac{\sqrt{942}}{-3.14} $
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