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300-(5+5x)x=0
We add all the numbers together, and all the variables
-(5x+5)x+300=0
We multiply parentheses
-5x^2-5x+300=0
a = -5; b = -5; c = +300;
Δ = b2-4ac
Δ = -52-4·(-5)·300
Δ = 6025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6025}=\sqrt{25*241}=\sqrt{25}*\sqrt{241}=5\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{241}}{2*-5}=\frac{5-5\sqrt{241}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{241}}{2*-5}=\frac{5+5\sqrt{241}}{-10} $
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