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30/x-20/(x-3)+4=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-3)!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
x!=3
x∈R
(30x-90)/(x^2-3x)+(-20x)/(x^2-3x)+4=0
We multiply all the terms by the denominator
(30x-90)+(-20x)+4*(x^2-3x)=0
We multiply parentheses
4x^2+(30x-90)+(-20x)-12x=0
We get rid of parentheses
4x^2+30x-20x-12x-90=0
We add all the numbers together, and all the variables
4x^2-2x-90=0
a = 4; b = -2; c = -90;
Δ = b2-4ac
Δ = -22-4·4·(-90)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-38}{2*4}=\frac{-36}{8} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+38}{2*4}=\frac{40}{8} =5 $
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