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30.25=3x(x-2)
We move all terms to the left:
30.25-(3x(x-2))=0
We calculate terms in parentheses: -(3x(x-2)), so:We get rid of parentheses
3x(x-2)
We multiply parentheses
3x^2-6x
Back to the equation:
-(3x^2-6x)
-3x^2+6x+30.25=0
a = -3; b = 6; c = +30.25;
Δ = b2-4ac
Δ = 62-4·(-3)·30.25
Δ = 399
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{399}}{2*-3}=\frac{-6-\sqrt{399}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{399}}{2*-3}=\frac{-6+\sqrt{399}}{-6} $
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