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30-x=22+1/2x
We move all terms to the left:
30-x-(22+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(1/2x+22)+30=0
We add all the numbers together, and all the variables
-1x-(1/2x+22)+30=0
We get rid of parentheses
-1x-1/2x-22+30=0
We multiply all the terms by the denominator
-1x*2x-22*2x+30*2x-1=0
Wy multiply elements
-2x^2-44x+60x-1=0
We add all the numbers together, and all the variables
-2x^2+16x-1=0
a = -2; b = 16; c = -1;
Δ = b2-4ac
Δ = 162-4·(-2)·(-1)
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{62}}{2*-2}=\frac{-16-2\sqrt{62}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{62}}{2*-2}=\frac{-16+2\sqrt{62}}{-4} $
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