30-(8+5x)-(3-24x)=29x-29-(31x-26)

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Solution for 30-(8+5x)-(3-24x)=29x-29-(31x-26) equation: 



30-(8+5x)-(3-24x)=29x-29-(31x-26)

We move all terms to the left:

30-(8+5x)-(3-24x)-(29x-29-(31x-26))=0

We add all the numbers together, and all the variables

-(5x+8)-(-24x+3)-(29x-29-(31x-26))+30=0

We get rid of parentheses

-5x+24x-(29x-29-(31x-26))-8-3+30=0



We calculate terms in parentheses: -(29x-29-(31x-26)), so:

29x-29-(31x-26)

determiningTheFunctionDomain
29x-(31x-26)-29

We get rid of parentheses

29x-31x+26-29

We add all the numbers together, and all the variables

-2x-3

Back to the equation:

-(-2x-3)



We add all the numbers together, and all the variables

19x-(-2x-3)+19=0

We get rid of parentheses

19x+2x+3+19=0

We add all the numbers together, and all the variables

21x+22=0

We move all terms containing x to the left, all other terms to the right

21x=-22

x=-22/21

x=-1+1/21

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