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30-(3x+3+2+4x)=72-(6x-1x-5)
We move all terms to the left:
30-(3x+3+2+4x)-(72-(6x-1x-5))=0
We add all the numbers together, and all the variables
-(7x+5)-(72-(5x-5))+30=0
We get rid of parentheses
-7x-(72-(5x-5))-5+30=0
We calculate terms in parentheses: -(72-(5x-5)), so:We add all the numbers together, and all the variables
72-(5x-5)
determiningTheFunctionDomain -(5x-5)+72
We get rid of parentheses
-5x+5+72
We add all the numbers together, and all the variables
-5x+77
Back to the equation:
-(-5x+77)
-7x-(-5x+77)+25=0
We get rid of parentheses
-7x+5x-77+25=0
We add all the numbers together, and all the variables
-2x-52=0
We move all terms containing x to the left, all other terms to the right
-2x=52
x=52/-2
x=-26
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