30-(3c+4)=2(c+7)+6

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Solution for 30-(3c+4)=2(c+7)+6 equation: 



30-(3c+4)=2(c+7)+6

We move all terms to the left:

30-(3c+4)-(2(c+7)+6)=0

We get rid of parentheses

-3c-(2(c+7)+6)-4+30=0



We calculate terms in parentheses: -(2(c+7)+6), so:

2(c+7)+6

We multiply parentheses

2c+14+6

We add all the numbers together, and all the variables

2c+20

Back to the equation:

-(2c+20)



We add all the numbers together, and all the variables

-3c-(2c+20)+26=0

We get rid of parentheses

-3c-2c-20+26=0

We add all the numbers together, and all the variables

-5c+6=0

We move all terms containing c to the left, all other terms to the right

-5c=-6

c=-6/-5

c=1+1/5

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