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30+z(z=5)
We move all terms to the left:
30+z(z-(5))=0
We multiply parentheses
z^2-5z+30=0
a = 1; b = -5; c = +30;
Δ = b2-4ac
Δ = -52-4·1·30
Δ = -95
Delta is less than zero, so there is no solution for the equation
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