30+10y=2(5y+2)+2(3y+4)

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Solution for 30+10y=2(5y+2)+2(3y+4) equation: 



30+10y=2(5y+2)+2(3y+4)

We move all terms to the left:

30+10y-(2(5y+2)+2(3y+4))=0



We calculate terms in parentheses: -(2(5y+2)+2(3y+4)), so:

2(5y+2)+2(3y+4)

We multiply parentheses

10y+6y+4+8

We add all the numbers together, and all the variables

16y+12

Back to the equation:

-(16y+12)



We get rid of parentheses

10y-16y-12+30=0

We add all the numbers together, and all the variables

-6y+18=0

We move all terms containing y to the left, all other terms to the right

-6y=-18

y=-18/-6

y=+3

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