30+(2x)+(5x-3)+(4x-5)+(4x+8)=360

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Solution for 30+(2x)+(5x-3)+(4x-5)+(4x+8)=360 equation: 



30+(2x)+(5x-3)+(4x-5)+(4x+8)=360

We move all terms to the left:

30+(2x)+(5x-3)+(4x-5)+(4x+8)-(360)=0

We add all the numbers together, and all the variables

2x+(5x-3)+(4x-5)+(4x+8)-330=0

We get rid of parentheses

2x+5x+4x+4x-3-5+8-330=0

We add all the numbers together, and all the variables

15x-330=0

We move all terms containing x to the left, all other terms to the right

15x=330

x=330/15

x=22

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