30(x-1)=5(6-x)+25x

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Solution for 30(x-1)=5(6-x)+25x equation: 



30(x-1)=5(6-x)+25x

We move all terms to the left:

30(x-1)-(5(6-x)+25x)=0

We add all the numbers together, and all the variables

30(x-1)-(5(-1x+6)+25x)=0

We multiply parentheses

30x-(5(-1x+6)+25x)-30=0



We calculate terms in parentheses: -(5(-1x+6)+25x), so:

5(-1x+6)+25x

We add all the numbers together, and all the variables

25x+5(-1x+6)

We multiply parentheses

25x-5x+30

We add all the numbers together, and all the variables

20x+30

Back to the equation:

-(20x+30)



We get rid of parentheses

30x-20x-30-30=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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