30(3x+1)=42(x+11)

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Solution for 30(3x+1)=42(x+11) equation: 



30(3x+1)=42(x+11)

We move all terms to the left:

30(3x+1)-(42(x+11))=0

We multiply parentheses

90x-(42(x+11))+30=0



We calculate terms in parentheses: -(42(x+11)), so:

42(x+11)

We multiply parentheses

42x+462

Back to the equation:

-(42x+462)



We get rid of parentheses

90x-42x-462+30=0

We add all the numbers together, and all the variables

48x-432=0

We move all terms containing x to the left, all other terms to the right

48x=432

x=432/48

x=9

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