30(1/2x+3)=20(x+2)

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Solution for 30(1/2x+3)=20(x+2) equation: 



30(1/2x+3)=20(x+2)

We move all terms to the left:

30(1/2x+3)-(20(x+2))=0



Domain of the equation: 2x+3)!=0

x∈R



We multiply parentheses

30x-(20(x+2))+90=0



We calculate terms in parentheses: -(20(x+2)), so:

20(x+2)

We multiply parentheses

20x+40

Back to the equation:

-(20x+40)



We get rid of parentheses

30x-20x-40+90=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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