3/y+3-1/y-2=5/2y+6

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Solution for 3/y+3-1/y-2=5/2y+6 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-(1/y)-2+3 = (5/2)*y+6 // - (5/2)*y+6

3/y-((5/2)*y)-(1/y)-6-2+3 = 0

(-5/2)*y+3/y-y^-1-6-2+3 = 0

2*y^-1-5/2*y^1-5*y^0 = 0

(2*y^0-5/2*y^2-5*y^1)/(y^1) = 0 // * y^2

y^1*(2*y^0-5/2*y^2-5*y^1) = 0

y^1

(-5/2)*y^2-5*y+2 = 0

(-5/2)*y^2-5*y+2 = 0

DELTA = (-5)^2-(2*4*(-5/2))

DELTA = 45

DELTA > 0

y = (45^(1/2)+5)/(2*(-5/2)) or y = (5-45^(1/2))/(2*(-5/2))

y = (3*5^(1/2)+5)/(-5) or y = (5-3*5^(1/2))/(-5)

y in { (3*5^(1/2)+5)/(-5), (5-3*5^(1/2))/(-5)}

y in { (3*5^(1/2)+5)/(-5), (5-3*5^(1/2))/(-5) }

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