3/y+2-4/2y+1=0

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Solution for 3/y+2-4/2y+1=0 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-((4/2)*y)+1+2 = 0

3/y-2*y+1+2 = 0

3*y^-1-2*y^1+3*y^0 = 0

(3*y^1-2*y^2+3*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^1-2*y^2+3*y^0) = 0

y^1

3*y-2*y^2+3 = 0

3*y-2*y^2+3 = 0

DELTA = 3^2-(-2*3*4)

DELTA = 33

DELTA > 0

y = (33^(1/2)-3)/(-2*2) or y = (-33^(1/2)-3)/(-2*2)

y = (33^(1/2)-3)/(-4) or y = (33^(1/2)+3)/4

y in { (33^(1/2)-3)/(-4), (33^(1/2)+3)/4} 

y in { (33^(1/2)-3)/(-4), (33^(1/2)+3)/4 }

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