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3/x=15/2x+6
We move all terms to the left:
3/x-(15/2x+6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+6)!=0We get rid of parentheses
x∈R
3/x-15/2x-6=0
We calculate fractions
6x/2x^2+(-15x)/2x^2-6=0
We multiply all the terms by the denominator
6x+(-15x)-6*2x^2=0
Wy multiply elements
-12x^2+6x+(-15x)=0
We get rid of parentheses
-12x^2+6x-15x=0
We add all the numbers together, and all the variables
-12x^2-9x=0
a = -12; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-12)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-12}=\frac{0}{-24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-12}=\frac{18}{-24} =-3/4 $
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