3/x=(3/2x)+3

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Solution for 3/x=(3/2x)+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x = (3/2)*x+3 // - (3/2)*x+3

3/x-((3/2)*x)-3 = 0

(-3/2)*x+3/x-3 = 0

3*x^-1-3/2*x^1-3*x^0 = 0

(3*x^0-3/2*x^2-3*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-3/2*x^2-3*x^1) = 0

x^1

(-3/2)*x^2-3*x+3 = 0

(-3/2)*x^2-3*x+3 = 0

DELTA = (-3)^2-(3*4*(-3/2))

DELTA = 27

DELTA > 0

x = (27^(1/2)+3)/(2*(-3/2)) or x = (3-27^(1/2))/(2*(-3/2))

x = (3*3^(1/2)+3)/(-3) or x = (3-3*3^(1/2))/(-3)

x in { (3*3^(1/2)+3)/(-3), (3-3*3^(1/2))/(-3)} 

x in { (3*3^(1/2)+3)/(-3), (3-3*3^(1/2))/(-3) }

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