3/x-4/x/4/3x+4/4x

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Solution for 3/x-4/x/4/3x+4/4x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/4)*x+3/x-((((4/x)/4)/3)*x) = 0

(4/4)*x+3/x-1/3 = 0

1*x^1+3*x^-1-1/3*x^0 = 0

(1*x^2-1/3*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-1/3*x^1+3*x^0) = 0

x^1

x^2+(-1/3)*x+3 = 0

x^2+(-1/3)*x+3 = 0

DELTA = (-1/3)^2-(1*3*4)

DELTA = -107/9

DELTA < 0

x in { } 

x belongs to the empty set

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