3/x-4+x-3/x=0

Solution for 3/x-4+x-3/x=0 equation:

3/x-4+x-3/x=0


Domain of the equation: x!=0

x∈R


We add all the numbers together, and all the variables

x+3/x-3/x-4=0

We multiply all the terms by the denominator


x*x-4*x+3-3=0

We add all the numbers together, and all the variables

-4x+x*x=0

Wy multiply elements

x^2-4x=0

a = 1; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·1·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*1}=\frac{8}{2}
=4
$