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3/x+5=11/4x
We move all terms to the left:
3/x+5-(11/4x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/x-(+11/4x)+5=0
We get rid of parentheses
3/x-11/4x+5=0
We calculate fractions
12x/4x^2+(-11x)/4x^2+5=0
We multiply all the terms by the denominator
12x+(-11x)+5*4x^2=0
Wy multiply elements
20x^2+12x+(-11x)=0
We get rid of parentheses
20x^2+12x-11x=0
We add all the numbers together, and all the variables
20x^2+x=0
a = 20; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·20·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*20}=\frac{-2}{40} =-1/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*20}=\frac{0}{40} =0 $
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