3/x+4/x+5/x+6/x=6-x

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Solution for 3/x+4/x+5/x+6/x=6-x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+4/x+5/x+6/x = 6-x // - 6-x

x+3/x+4/x+5/x+6/x-6 = 0

1*x^1+18*x^-1-6*x^0 = 0

(1*x^2-6*x^1+18*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-6*x^1+18*x^0) = 0

x^1

x^2-6*x+18 = 0

x^2-6*x+18 = 0

DELTA = (-6)^2-(1*4*18)

DELTA = -36

DELTA < 0

x in { } 

x belongs to the empty set

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