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3/x+2=6x-4x+8
We move all terms to the left:
3/x+2-(6x-4x+8)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3/x-(2x+8)+2=0
We get rid of parentheses
3/x-2x-8+2=0
We multiply all the terms by the denominator
-2x*x-8*x+2*x+3=0
We add all the numbers together, and all the variables
-6x-2x*x+3=0
Wy multiply elements
-2x^2-6x+3=0
a = -2; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·(-2)·3
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{15}}{2*-2}=\frac{6-2\sqrt{15}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{15}}{2*-2}=\frac{6+2\sqrt{15}}{-4} $
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