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3/x+2/x+1=3/5x
We move all terms to the left:
3/x+2/x+1-(3/5x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/x+2/x-(+3/5x)+1=0
We get rid of parentheses
3/x+2/x-3/5x+1=0
We calculate fractions
(10x+3)/5x^2+(-3x)/5x^2+1=0
We multiply all the terms by the denominator
(10x+3)+(-3x)+1*5x^2=0
Wy multiply elements
5x^2+(10x+3)+(-3x)=0
We get rid of parentheses
5x^2+10x-3x+3=0
We add all the numbers together, and all the variables
5x^2+7x+3=0
a = 5; b = 7; c = +3;
Δ = b2-4ac
Δ = 72-4·5·3
Δ = -11
Delta is less than zero, so there is no solution for the equation
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