3/p+3=p+4/2

Solution for 3/p+3=p+4/2 equation:

3/p+3=p+4/2

We move all terms to the left:

3/p+3-(p+4/2)=0


Domain of the equation: p!=0

p∈R


We add all the numbers together, and all the variables

3/p-(p+2)+3=0

We get rid of parentheses

3/p-p-2+3=0

We multiply all the terms by the denominator


-p*p-2*p+3*p+3=0

We add all the numbers together, and all the variables

p-p*p+3=0

Wy multiply elements

-1p^2+p+3=0

a = -1; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-1)·3
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{13}}{2*-1}=\frac{-1-\sqrt{13}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{13}}{2*-1}=\frac{-1+\sqrt{13}}{-2}
$