3/n-40+2n=15

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Solution for 3/n-40+2n=15 equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2*n+3/n-40 = 15 // - 15

2*n+3/n-40-15 = 0

2*n^1+3*n^-1-55*n^0 = 0

(2*n^2-55*n^1+3*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^2-55*n^1+3*n^0) = 0

n^1

2*n^2-55*n+3 = 0

2*n^2-55*n+3 = 0

DELTA = (-55)^2-(2*3*4)

DELTA = 3001

DELTA > 0

n = (3001^(1/2)+55)/(2*2) or n = (55-3001^(1/2))/(2*2)

n = (3001^(1/2)+55)/4 or n = (55-3001^(1/2))/4

n in { (55-3001^(1/2))/4, (3001^(1/2)+55)/4}

n in { (55-3001^(1/2))/4, (3001^(1/2)+55)/4 }

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