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3/k+3=8/k-2
We move all terms to the left:
3/k+3-(8/k-2)=0
Domain of the equation: k!=0
k∈R
Domain of the equation: k-2)!=0We get rid of parentheses
k∈R
3/k-8/k+2+3=0
We multiply all the terms by the denominator
2*k+3*k+3-8=0
We add all the numbers together, and all the variables
5k-5=0
We move all terms containing k to the left, all other terms to the right
5k=5
k=5/5
k=1
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