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3/8x+1/5x=45
We move all terms to the left:
3/8x+1/5x-(45)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
15x/40x^2+8x/40x^2-45=0
We multiply all the terms by the denominator
15x+8x-45*40x^2=0
We add all the numbers together, and all the variables
23x-45*40x^2=0
Wy multiply elements
-1800x^2+23x=0
a = -1800; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-1800)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-1800}=\frac{-46}{-3600} =23/1800 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-1800}=\frac{0}{-3600} =0 $
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