3/8x+1/3x=20

Solution for 3/8x+1/3x=20 equation:

3/8x+1/3x=20

We move all terms to the left:

3/8x+1/3x-(20)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


9x/24x^2+8x/24x^2-20=0

We multiply all the terms by the denominator


9x+8x-20*24x^2=0

We add all the numbers together, and all the variables

17x-20*24x^2=0

Wy multiply elements

-480x^2+17x=0

a = -480; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-480)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-480}=\frac{-34}{-960}
=17/480
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-480}=\frac{0}{-960}
=0
$