3/8(x+3)=4/8(x+1)

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Solution for 3/8(x+3)=4/8(x+1) equation: 



3/8(x+3)=4/8(x+1)

We move all terms to the left:

3/8(x+3)-(4/8(x+1))=0



Domain of the equation: 8(x+3)!=0

x∈R





Domain of the equation: 8(x+1))!=0

x∈R



We calculate fractions


(24xx/(8(x+3)*8(x+1)))+(-32xx/(8(x+3)*8(x+1)))=0



We calculate terms in parentheses: +(24xx/(8(x+3)*8(x+1))), so:

24xx/(8(x+3)*8(x+1))

We multiply all the terms by the denominator


24xx

Back to the equation:

+(24xx)





We calculate terms in parentheses: +(-32xx/(8(x+3)*8(x+1))), so:

-32xx/(8(x+3)*8(x+1))

We multiply all the terms by the denominator


-32xx

Back to the equation:

+(-32xx)



We get rid of parentheses

24xx-32xx=0

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