3/8(4a-5)-5/12(3a-4)=1/4

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Solution for 3/8(4a-5)-5/12(3a-4)=1/4 equation: 



3/8(4a-5)-5/12(3a-4)=1/4

We move all terms to the left:

3/8(4a-5)-5/12(3a-4)-(1/4)=0



Domain of the equation: 8(4a-5)!=0

a∈R





Domain of the equation: 12(3a-4)!=0

a∈R



We add all the numbers together, and all the variables

3/8(4a-5)-5/12(3a-4)-(+1/4)=0

We get rid of parentheses

3/8(4a-5)-5/12(3a-4)-1/4=0

We calculate fractions


(144a3/(8(4a-5)*12(3a-4)*4)+(-160a4/(8(4a-5)*12(3a-4)*4)+(-96a^24/(8(4a-5)*12(3a-4)*4)=0



We calculate terms in parentheses: +(144a3/(8(4a-5)*12(3a-4)*4)+(-160a4/(8(4a-5)*12(3a-4)*4)+(-96a^24/(8(4a-5)*12(3a-4)*4), so:

144a3/(8(4a-5)*12(3a-4)*4)+(-160a4/(8(4a-5)*12(3a-4)*4)+(-96a^24/(8(4a-5)*12(3a-4)*4

We do not support eapression: a^24

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