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3/7x+9=x-7
We move all terms to the left:
3/7x+9-(x-7)=0
Domain of the equation: 7x!=0We get rid of parentheses
x!=0/7
x!=0
x∈R
3/7x-x+7+9=0
We multiply all the terms by the denominator
-x*7x+7*7x+9*7x+3=0
Wy multiply elements
-7x^2+49x+63x+3=0
We add all the numbers together, and all the variables
-7x^2+112x+3=0
a = -7; b = 112; c = +3;
Δ = b2-4ac
Δ = 1122-4·(-7)·3
Δ = 12628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12628}=\sqrt{4*3157}=\sqrt{4}*\sqrt{3157}=2\sqrt{3157}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-2\sqrt{3157}}{2*-7}=\frac{-112-2\sqrt{3157}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+2\sqrt{3157}}{2*-7}=\frac{-112+2\sqrt{3157}}{-14} $
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