3/7x+8/x=1

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Solution for 3/7x+8/x=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/7)*x+8/x = 1 // - 1

(3/7)*x+8/x-1 = 0

3/7*x^1+8*x^-1-1*x^0 = 0

(3/7*x^2-1*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(3/7*x^2-1*x^1+8*x^0) = 0

x^1

(3/7)*x^2-x+8 = 0

(3/7)*x^2-x+8 = 0

DELTA = (-1)^2-(4*8*(3/7))

DELTA = -89/7

DELTA < 0

x in { } 

x belongs to the empty set

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