3/7=(a+2)/6

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Solution for 3/7=(a+2)/6 equation: 



3/7=(a+2)/6

We move all terms to the left:

3/7-((a+2)/6)=0

We calculate fractions


(-((a+2)*7)/()+()/()=0



We calculate terms in parentheses: +(-((a+2)*7)/()+()/(), so:

-((a+2)*7)/()+()/(

We add all the numbers together, and all the variables

-((a+2)*7)/()+1

We multiply all the terms by the denominator


-((a+2)*7)+1*()



We calculate terms in parentheses: -((a+2)*7), so:

(a+2)*7

We multiply parentheses

7a+14

Back to the equation:

-(7a+14)



We add all the numbers together, and all the variables

-(7a+14)

We get rid of parentheses

-7a-14

Back to the equation:

+(-7a-14)



We get rid of parentheses

-7a-14=0

We move all terms containing a to the left, all other terms to the right

-7a=14

a=14/-7

a=-2

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