3/7(x+1)=1/21(x+8)

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Solution for 3/7(x+1)=1/21(x+8) equation: 



3/7(x+1)=1/21(x+8)

We move all terms to the left:

3/7(x+1)-(1/21(x+8))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 21(x+8))!=0

x∈R



We calculate fractions


(63xx/(7(x+1)*21(x+8)))+(-7xx/(7(x+1)*21(x+8)))=0



We calculate terms in parentheses: +(63xx/(7(x+1)*21(x+8))), so:

63xx/(7(x+1)*21(x+8))

We multiply all the terms by the denominator


63xx

Back to the equation:

+(63xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*21(x+8))), so:

-7xx/(7(x+1)*21(x+8))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

63xx-7xx=0

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