3/7(2p-14)=6/7p-6

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Solution for 3/7(2p-14)=6/7p-6 equation: 


p in (-oo:+oo)

(3/7)*(2*p-14) = (6/7)*p-6 // - (6/7)*p-6

(3/7)*(2*p-14)-((6/7)*p)+6 = 0

(3/7)*(2*p-14)+(-6/7)*p+6 = 0

3/7*(2*p-14)+(-6*p)/7+6 = 0

(3/7*7*(2*p-14))/7+(-6*p)/7+(6*7)/7 = 0

3/7*7*(2*p-14)-6*p+6*7 = 0

42-42 = 0

0 = 0

0/7 = 0

0/7 = 0 // * 7

0 = 0

p belongs to the empty set

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