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3/5y-2y=-7/5y
We move all terms to the left:
3/5y-2y-(-7/5y)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 5y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-2y+3/5y-(-7/5y)=0
We get rid of parentheses
-2y+3/5y+7/5y=0
We multiply all the terms by the denominator
-2y*5y+3+7=0
We add all the numbers together, and all the variables
-2y*5y+10=0
Wy multiply elements
-10y^2+10=0
a = -10; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-10)·10
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-10}=\frac{-20}{-20} =1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-10}=\frac{20}{-20} =-1 $
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